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Day-1 | Aptitude Questions and Answers with Explanation

  • Question -1
  • Explanation
1. Find the missing number in the sequence 2, 5, 4, 7, _

a) 6       b) 4        c) 5          d) 7

Answer: 6

Just consider the sequence 3,4,5,6,7 and start subtracting and adding 1 to consecutive numbers which will get you sequence in question.

  • Question -2
  • Explanation

2. Find the missing number in 0, 4, 5, 11_

a)12            b)13            c)14            d)15

Answer: 14

Whenever you find a sequence like 0,4,5,11 with hardly any relation between adjacent numbers, it is wiser to try adding and subtracting small numbers like 1 or 2 to all numbers. Now alternatively adding 1and subtracting 1 from each number of sequence we get 1,3,6,10. This sequence has got a pattern!

The first digit “1” is the sum of first “1” natural numbers. second digit “3” is the sum of first “2” natural numbers, and the third digit “3” is the sum of first “2” natural numbers, and the third digit”6” is the sum of first “3” natural numbers and so on.

Hence the final digit in the modified sequence would be 15 which is the sum of first 5 natural numbers. we need to subtract 1 from 15 so that it fits the sequence in question. Hence the answer is 14.

  • Question -3
  • Explanation

3.What is the Percentage increase in area when triangle is cloned(so that we have two triangles in total) and the resulting two triangles are joined on their bases to form a parallelogram?

a.100%                b.150%                c.300%                d.120%     7

Answer: 100%

Area of a triangle with base b and height h is given by ½(b X h)

When two triangles are mounted on their bases to form s parallelogram, the area would become (b X h)

Percentage increase of area= (new area-area of the original triangle)/ (area of the original triangle) X 100%

= (b X h)-1/2(b/h) / ½(b X h) X 100%

= (1-1/2) / (1/2)X100%

=100%

  • Question-4
  • Explanation
4.Consider three people A, B, C . let A and B can finish a job in 21 days and C in 14 days and A and C in 28 days.who will take the least time when working independently?

1. A        2.B        3.C        D. Cant be determined

Answer: B

Consider WA, WB and WC be the work done per day by A, B, C respectively .then

WA+WB=1/21    –eq1

WB+WC=1/14    –eq2

WA=WC=1/28    –eq3

Eq2-Eq3 will give

WB-WA=1/14-1/28=1/28 –eq4

Eq1+Eq4 will give

2WB=1/21+1/28=7/84

WB=7/168

Sub value of WB IN eq 1,we get

WA=1/21-7/168=1/168

Sub value of WA in eq3,we get

WC=1/128-WA=1/128-1/168=5/168

Since WB (work done by  B per day) is greater when compared to WA and WB clearly B will be able to do the maximum work on any given day and hence he should consume least amount of time when working independently.

  • Question – 5
  • Explanation
5.consider two postmen A and B respectively.A is young and can deliver 20 parcels in 3 hours while B is older than A and can deliver only 15 parcels in 4 hours.if the total number of parcels to deliver is 60.how long they will take working together?

a.121/12 hours      b.144/36 hours        c.144/25 hours    d.121/25 hours

Answer:144/25 hours.

A can deliver 20 parcels in 3 hourse.Hence for 1 hour

He can deliver 20/3 parcels.

B can deliver 15 parcels in 4 hr.hence for 1 hr B can deliver ,20/3+15/4 parcels=80+45/12=125/12 parcels.

Hence to deliver 60 parcels they would require: 60X12/125=720/125=144/25 hr.

 

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