# Day-4 | Aptitude Questions and Answers with Explanation

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[divider] [tabs type=”horizontal”] [tabs_head][tab_title]Question-1[/tab_title][tab_title]Explanation[/tab_title][/tabs_head] [tab]

John is supposed to walk from his house to park every morning. One morning he is in real hurry and wants to save atleast 1/3rd of the time. By how much percentage he should increase his speed.

a).100%    b)33%     c) 66%        d) 50%

[/tab] [tab]Answer:

d) 50%

Let the distance between his house and park be 100 metres.

Let’s assume he takes 30 minutes daily. Hence his speed would be 100/30.

One day, if he wishes to save 1/3rd of 30 minutes, that is 10 minutes, he should cover the distance in 20 minutes in which case his speed would be 100/20.

Required increment in speed = (Required increment in speed / Original Speed) * 100 % = ((100/20 – 100/30)/100/30)* 100% = 50%

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[tabs type=”horizontal”] [tabs_head][tab_title]Question-3[/tab_title][tab_title]Explanation[/tab_title][/tabs_head] [tab]

Can you give a simple formula to find average of sum of squares of first n natural numbers?[/tab] [tab]

Answer: d)

(n + 1) (2n + 1) /6 can be used to calculate the average of sum of first n natural numbers.

[/tab][/tabs] [divider] [tabs type=”horizontal”] [tabs_head][tab_title]Question-3[/tab_title][tab_title]Explanation[/tab_title][/tabs_head] [tab]

Given Log x (ab) and logx (a/b), how you will find logx a

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Answer: d)

:  Log x (ab) can be written as logx (a) + logx (b) ……..equation 1.

logx (a/b) can be written as logx (a)  – logx (b) ……..equation 2.

Solving equation 1 and 2 we will get  logx (a) =  Log x (ab) + logx (a/b)/ 2)

[/tab][/tabs] [divider] [tabs type=”horizontal”] [tabs_head][tab_title]Question-4[/tab_title][tab_title]Explanation[/tab_title][/tabs_head] [tab]

Consider a rhombus with diagonals of lengths d1 and d2. What could be its area?

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Answer:

Area of the rhombus = ½(d1 * d2)

[/tab][/tabs] [divider] [tabs type=”horizontal”] [tabs_head][tab_title]Question-5[/tab_title][tab_title]Explanation[/tab_title][/tabs_head] [tab]

Can you quickly tell the ratio of the volume of a cylinder of height h to that of another cylinder of unit height but with same radius?

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Answer:

Height h is the answer.

Reason: Volume V1 of Cylinder of height h and radius r, V1 = IIr2 h

Volume V2 of another Cylinder of unit height of same radius r,

V2 = IIr2h /9by substituting 1 for h) Now answer is V1/V2 = h.

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